http://www.purplemath.com/modules/strtlneq.htm http://www.purplemath.com/modules/intrcept.htm
While looking for a slope of a line you first must put it in slope intercept form.
y=mx+b
b the y intercept. you know how to graph this by if it is a positive or a negative. if it is a positive you will graph above the x axis. if it is negative then you will graph below the x axis.
y=4x-2
for this line you need to go to the origin and go down 2 spaces because the number is negative.
then after graphing that point you need to go up 4 spaces and over 1. this makes this line positive because it is increasing.
you don't have to graph this in order to find the points of intersection.
first set y equal to zero in the problem
now you need to find x so set x as 0.
http://www.purplemath.com/modules/intrcept.htm
While looking for a slope of a line you first must put it in slope intercept form.
y=mx+b
b the y intercept. you know how to graph this by if it is a positive or a negative. if it is a positive you will graph above the x axis. if it is negative then you will graph below the x axis.
y=4x-2
for this line you need to go to the origin and go down 2 spaces because the number is negative.
then after graphing that point you need to go up 4 spaces and over 1. this makes this line positive because it is increasing.
you don't have to graph this in order to find the points of intersection.
first set y equal to zero in the problem
now you need to find x so set x as 0.